Quiz CHALLENGE RS Aggarwal Maths Class - 4th ( S. CHAND School Book )

 Quiz CHALLENGE RS Aggarwal Maths Class - 4th ( S. CHAND School Book )

Here are the solutions to each question:  




Page 1:

  1. Find the difference between the largest and the smallest 5-digit odd numbers using the digits 7, 4, 9, 2, and 6.

    • Largest odd number: 97641
    • Smallest odd number: 12467
    • Difference: 97641 - 12467 = 85174
    • None of the options match exactly, so there might be an error in the given choices.
  2. Komal works for 6 days in a week, 6 hours 15 minutes daily. How long does she work in a week?

    • 6×6.25=37.56 \times 6.25 = 37.5 hours
    • Answer: (b) 37 hours 30 minutes
  3. A factory produces 18 TV units each day. How many in 6 weeks?

    • 18×42=75618 \times 42 = 756
    • Answer: (b) 756
  4. Which shape has the maximum number of lines of symmetry?

    • Equilateral triangle has 3, square has 4.
    • Answer: (c) Square
  5. Multiply the number of months having 31 days with the number of months having 30 days.

    • There are 7 months with 31 days and 4 months with 30 days
    • 7×4=287 \times 4 = 28
    • Answer: (a) 28
  6. Find the 20th term of the sequence:

    • The pattern is: 1,2,2,3,3,3,4,4,4,4,5,5,5,5,5,6,6,6,6,6,6...1,2,2,3,3,3,4,4,4,4,5,5,5,5,5,6,6,6,6,6,6...
    • The number n appears n times
    • The 20th term falls in the group of 6’s
    • Answer: (b) 6
  7. Find the missing number in the pattern.

    • The pattern suggests summation of numbers in a structured way.
    • The missing number is 87.
    • Answer: (c) 87
  8. How many chords are in the given circle diagram?

    • The diagram has 6 chords.
    • Answer: (c) 6
  9. How many letters of the English alphabet have more than one line of symmetry?

    • Letters: A, H, I, M, O, T, U, V, W, X, Y
    • Those with more than one: A, H, I, O, X
    • Answer: (b) 5

Page 2

10. Anu multiplies the 5th multiple of 5 by the 4th multiple of 4.

  • (5×5)×(4×4)=25×16=400
  • Answer: (b) 400

11. Number of ways to go from A to C via B.

  • 3×8=24
  • Answer: (d) 24

12. Digits that remain in order in 321465987.

  • Only 2 digits remain in order.
  • Answer: (b) Two

13. How many numbers between 50 and 100 are multiples of 6?

  • {54,60,66,72,78,84,90,96}
  • 8 numbers
  • Answer: (b) 8

14. Numbers from 1 to 100 that are multiples of both 3 and 4.

  • LCM(3,4)=12
  • Multiples of 12: {12,24,36,48,60,72,84,96}
  • 8 numbers
  • Answer: (a) 8

15. How many 1/8 are in 3 1/2?

  • 312=72
  • 72÷18=7×4=28
  • Answer: (c) 28

16. Cutting corners of a square - perimeter and area.

  • Perimeter increases, area decreases.
  • Answer: (b) Perimeter of X > Perimeter of Y, Area of X > Area of Y

17. Figure with a line of symmetry.

  • The correct figure has symmetry (option b).
  • Answer: (b)

18. Difference between place value of tens digit of greatest number and face value of ones digit of smallest number using 7, 2, 3, 8, 4.

  • Greatest number: 87432 (Tens digit = 3, place value = 30)
  • Smallest number: 23478 (Ones digit = 8, face value = 8)
  • Difference = 30 - 8 = 22
  • Answer: (c) 22

Page 3

19. Find the perimeter of the given figure.

  • The given figure is a step-like shape with unit squares.
  • Counting all the external sides, the perimeter = 44 cm.
  • Answer: (b) 44 cm

20. The time 3 hours 50 minutes after 11:40 a.m.

  • 11:40+3:50=3:30 p.m.11:40 + 3:50 = 3:30 \text{ p.m.}
  • Answer: (c) 3:30 p.m.

21. What fraction of the given figure is shaded?

  • The figure consists of 36 small squares, with 7 shaded.
  • Fraction = 7/36.
  • Answer: (d) 7/36

22. Combined cost of 3 kg apples, 6 kg oranges, and 5 kg watermelons.

  • Apples: 2805×3=168 \frac{280}{5} \times 3 = 168
  • Oranges: 1764×6=264 \frac{176}{4} \times 6 = 264
  • Watermelons: 2088×5=130 \frac{208}{8} \times 5 = 130
  • Total = 168 + 264 + 130 = 562
  • Answer: (b) ₹562

**23. Smallest possible number for * when 2304 ÷ 4 < 6 * ***

  • 2304÷4=5762304 \div 4 = 576
  • Find * such that 576<6576 < 6*:
  • >96* > 96, smallest integer is 97.
  • Answer: (c) 97

24. Find the value of (🍏 + 🍏 + 🍏) using given conditions.

  • Using the equations, solving gives 1440.
  • Answer: (c) 1440

25. Difference between largest odd and smallest even number from 2, 5, 4, 7, 9.

  • Largest odd: 97541
  • Smallest even: 24578
  • Difference: 97541 - 24578 = 72963
  • Answer: (d) 97245

26. Checking statements:

  • (I) True, (II) False, (III) True, (IV) True
  • Answer: (c) 3 statements correct

27. How many children left in the hall?

  • Boys left: 15×825=165 \frac{1}{5} \times 825 = 165
  • Girls left: 16×438=73 \frac{1}{6} \times 438 = 73
  • Remaining: 825165+43873=1025825 - 165 + 438 - 73 = 1025
  • Answer: (c) 1025

Page 4


28. School timing calculation

  • Start time: 7:50 a.m.
  • Work duration: 5 hours 15 minutes
  • Lunch break: 35 minutes
  • Total time: 5h 15m + 35m = 5h 50m
  • End time: 7:50 a.m. + 5h 50m = 1:40 p.m.
  • Answer: (b) 1:40 p.m.

29. Cost of 1 kg wheat flour

  • Given: 300 gm costs ₹12
  • Cost per gram: 12 ÷ 300 = ₹0.04 per gram
  • Cost of 1 kg (1000 gm): 1000 × 0.04 = ₹40
  • Answer: (b) ₹40

30. Find the smaller number

  • Given:
    • x - y = 64
    • x + y = 236
  • Solving:
    • 2x = 300 → x = 150
    • y = 150 - 64 = 86
  • Answer: (c) 86

31. Three-digit even numbers using 0,3,6 without repetition

  • Three-digit even numbers: Must end in 0 or 6
  • Case 1 (Ending in 0): Choices for first digit: 3, 6 → 2 choices
    • Second digit: 1 choice
  • Case 2 (Ending in 6): Choices for first digit: 3 → 1 choice
    • Second digit: 1 choice
  • Total = 2 + 1 = 3
  • Answer: (a) 3

32. Total money Ajay has

  • 2 × ₹500 = ₹1000
  • 3 × ₹100 = ₹300
  • 4 × ₹50 = ₹200
  • 5 × ₹20 = ₹100
  • 6 × ₹10 = ₹60
  • 7 × ₹5 = ₹35
  • Total = ₹1000 + ₹300 + ₹200 + ₹100 + ₹60 + ₹35 = ₹1695
  • Answer: (d) ₹1695

33. Number of triangles in the given figure

  • Careful counting gives 18 triangles
  • Answer: (d) 18

34. Place value of 5 in 49563

  • Place value of 5 = 5000
  • Face value of 5 = 5
  • Difference = 5000 - 5 = 4995
  • Answer: (b) 4995

35. Total gain/loss in Sumit’s deal

  • First transaction:
    • Bought at ₹3200, sold at ₹3560 → Gain of ₹360
  • Second transaction:
    • Bought at ₹3300, sold at ₹3150 → Loss of ₹150
  • Third transaction:
    • Bought at ₹3200, sold at ₹3280 → Gain of ₹80
  • Net Gain = 360 - 150 + 80 = ₹290
  • Answer: (a) ₹290 gain

36. Find the weekday of 27th August

  • Given 2nd August is Wednesday
  • Days forward:
    • 2nd Aug → Wednesday
    • 9th Aug → Wednesday
    • 16th Aug → Wednesday
    • 23rd Aug → Wednesday
    • 27th Aug → Sunday
  • Answer: (c) Sunday

37. Identify the non-leap year

  • Leap years are divisible by 4 (except century years, which must be divisible by 400)
  • 1998 is not divisible by 4 → Not a leap year
  • Answer: (a) 1998

38. Find the difference between smallest and greatest P where 2014 ÷ P leaves remainder 5

  • Possible values: 2014 - 5 = 2009
  • Factors of 2009: 7 × 7 × 41
  • Smallest P = 7, Largest P = 2009
  • Difference = 2009 - 7 = 2002
  • Answer: (b) 2002

39. Convert feet to cm

  • 1 foot = 12 inches
  • 1 inch = 2.5 cm
  • 4 feet = 4 × 12 × 2.5 = 120 cm
  • Answer: (b) 120

40. Number of cold drinks Aryan can get

  • ₹200 at ₹20 per can10 cans
  • Free drinks:
    • 10 cans → 10 empty cans
    • 10 ÷ 4 = 2 extra drinks
    • New total = 10 + 2 = 12
  • Answer: (b) 12

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